A complex situation. White cannot prevent Black
from recycling pieces. If he prevents it on the a3-g1 line, he'll
always create another possibility.
White knows that if Black plays 1...b1-f4;x (and, as things
are for the moment, he must do so), he'll push the white GIPF
on e4 onto f4. With that in mind, White plays
1.b6-g4 and pushes another of his GIPF-pieces into a good
position (i.e. onto f5, diagram below).
The GIPF-piece on f5
doesn't look dangerous yet, but it will become a threat... with
White created for Black a second way to recycle pieces (i.e. on
the g1-g7 line). Black has the choice between 1...b1-f4;x
or i5-d4;x. No matter which of the two moves he'll choose,
he'll put his Gd5 in danger, because White will
make the move Black didn't make! So, 1...i5-d4;x will be
followed by 2.b1-f4, through which White forces Black to
remove pieces either on the d1-d8 line or on the a3-g1 line. This
manoeuvre costs White two pieces, but he has 2 GIPF-pieces attacking
Gd5 now, and, even more important, he made that Black has
no pieces left on the side of the board where he established his
attack. (diagram below).
If i5-d4 and b1-f4 would have been
played in reversed order, the result would have been exactly the
same. It also makes no difference whether Black captures on the
a3-g1 line or on the d1-d8 line. If he chooses xd2,d3,d4,d6,
he would leave himself 2...a2-f6 to push his GIPF away
from the dangerous d5-spot, but the white piece on f2
makes that escape impossible. So, the only thing Black can do
to postpone losing his GIPF-piece (no matter which row he removed),
is pushing the piece on h2 towards g2 or h3.
But that postpones it just with one move: White occupies g3
with his third move and captures Black's GIPF with his fourth
move. White wins with 4 moves, which is the shortest way!